http://acktckhahoun.blogspot.com/
#define mod(n) do { \
static int i = 0; \
box1[i] = a * 255 % n; \
box2[i] = b * 255 % n; \
box3[i] = c * 255 % n; \
box4[i] = n; \
i++; \
} while(0);
char box1[255];
char box2[255];
char box3[255];
char box4[255];
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build box mod n over 1 seline 2poet seline 3 poet seline 4 poetseline mod n seline mod box n
echo #PRAGMA 0 - 1 coseiyene aor coseine
aor annswers hal cant sayis "its cozy"
Monday, February 6, 2017
Tuesday, January 10, 2017
#include <stdio.h>
#define a 'b'
#define b 'c'
#define c 'a'
#define mod(n) do { \
static int i = 0; \
box1[i] = a * 255 % n; \
box2[i] = b * 255 % n; \
box3[i] = c * 255 % n; \
box4[i] = n; \
i++; \
} while(0);
char box1[255];
char box2[255];
char box3[255];
char box4[255];
int main()
{
char n;
do {
static int i = 0;
n = getchar();
mod(n)
fprintf(stderr, "\n b1: %c, b2: %c, b3: %c, b4: %c ", box1[i], box2[i], box3[i], box4[i]);
i++;
} while (1);
return 0;
}
~
#define a 'b'
#define b 'c'
#define c 'a'
#define mod(n) do { \
static int i = 0; \
box1[i] = a * 255 % n; \
box2[i] = b * 255 % n; \
box3[i] = c * 255 % n; \
box4[i] = n; \
i++; \
} while(0);
char box1[255];
char box2[255];
char box3[255];
char box4[255];
int main()
{
char n;
do {
static int i = 0;
n = getchar();
mod(n)
fprintf(stderr, "\n b1: %c, b2: %c, b3: %c, b4: %c ", box1[i], box2[i], box3[i], box4[i]);
i++;
} while (1);
return 0;
}
~
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